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Part IA Michaelmas, Lent, Easter Term

Integration Fundamentals

The Integral as Limit of a Sum

The Riemann integral is defined as:

∫abf(x) dx=lim⁡N→∞∑i=1Nf(xi) δx\int_a^b f(x)\,dx = \lim_{N \to \infty} \sum_{i=1}^{N} f(x_i)\,\delta x

where δx=(b−a)/N\delta x = (b-a)/N and xix_i are sample points in each subinterval.

Interpretation: Area under the curve, with rectangles becoming infinitesimally thin.


Fundamental Theorem of Calculus

First form: If F′(x)=f(x)F'(x) = f(x), then:

∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx = F(b) - F(a)

Second form: Define:

F(x)=∫axf(t) dtF(x) = \int_a^x f(t)\,dt

Then F′(x)=f(x)F'(x) = f(x).

Significance: Differentiation and integration are inverse operations.


Differentiation Under the Integral Sign

For I(q)=∫abf(x,q) dxI(q) = \int_a^b f(x, q)\,dx:

dIdq=∫ab∂f∂q dx\frac{dI}{dq} = \int_a^b \frac{\partial f}{\partial q}\,dx

If limits depend on qq:

ddq∫a(q)b(q)f(x,q) dx=f(b,q)dbdq−f(a,q)dadq+∫ab∂f∂q dx\frac{d}{dq}\int_{a(q)}^{b(q)} f(x, q)\,dx = f(b, q)\frac{db}{dq} - f(a, q)\frac{da}{dq} + \int_a^b \frac{\partial f}{\partial q}\,dx


Standard Techniques

Substitution

∫f(g(x))g′(x) dx=∫f(u) duwhere u=g(x)\int f(g(x))g'(x)\,dx = \int f(u)\,du \quad \text{where } u = g(x)

Example: ∫2xcos⁡(x2) dx\int 2x\cos(x^2)\,dx. Let u=x2u = x^2, du=2x dxdu = 2x\,dx:

∫cos⁡u du=sin⁡u=sin⁡(x2)\int \cos u\,du = \sin u = \sin(x^2)

Integration by Parts

∫u dvdx dx=uv−∫v dudx dx\int u\,\frac{dv}{dx}\,dx = uv - \int v\,\frac{du}{dx}\,dx

Example: ∫xex dx\int x e^x\,dx.

Let u=xu = x, dv=ex dxdv = e^x\,dx. Then du=dxdu = dx, v=exv = e^x:

∫xex dx=xex−∫ex dx=xex−ex+C\int x e^x\,dx = xe^x - \int e^x\,dx = xe^x - e^x + C

Partial Fractions

For rational functions, decompose into simpler fractions.

1(x−1)(x+2)=Ax−1+Bx+2\frac{1}{(x-1)(x+2)} = \frac{A}{x-1} + \frac{B}{x+2}

Solving: 1=A(x+2)+B(x−1)1 = A(x+2) + B(x-1). At x=1x = 1: A=1/3A = 1/3. At x=−2x = -2: B=−1/3B = -1/3.


Improper Integrals

Type 1: Infinite limits

∫a∞f(x) dx=lim⁡b→∞∫abf(x) dx\int_a^{\infty} f(x)\,dx = \lim_{b \to \infty} \int_a^b f(x)\,dx

Converges if limit exists (finite).

Type 2: Unbounded integrand

∫abdxx−a=lim⁡ε→0+∫a+εbdxx−a\int_a^b \frac{dx}{\sqrt{x-a}} = \lim_{\varepsilon \to 0^+} \int_{a+\varepsilon}^b \frac{dx}{\sqrt{x-a}}

Comparison test for improper integrals

If 0≤f(x)≤g(x)0 \leq f(x) \leq g(x) and ∫g\int g converges, then ∫f\int f converges.


Symmetry and Integration

Even function: f(−x)=f(x)f(-x) = f(x)

∫−aaf(x) dx=2∫0af(x) dx\int_{-a}^{a} f(x)\,dx = 2\int_0^a f(x)\,dx

Odd function: f(−x)=−f(x)f(-x) = -f(x)

∫−aaf(x) dx=0\int_{-a}^{a} f(x)\,dx = 0

Even function (symmetric) and odd function (antisymmetric) showing integration areas that cancel or double

This simplifies many integrals, especially for trigonometric and polynomial terms.


Mean Value Theorem for Integrals

For continuous ff on [a,b][a, b], there exists c∈[a,b]c \in [a, b] such that:

∫abf(x) dx=f(c)(b−a)\int_a^b f(x)\,dx = f(c)(b - a)

The integral equals the function value at some point times the interval width.


Integration by Inspection

Recognise standard forms and their derivatives:

IntegralResult
∫f′f dx\int \frac{f'}{f}\,dxln⁡∥f∥\ln\|f\|
∫f′(x)[f(x)]n dx\int f'(x)[f(x)]^n\,dx[f(x)]n+1n+1\frac{[f(x)]^{n+1}}{n+1}
∫1a2+x2 dx\int \frac{1}{a^2 + x^2}\,dx1atan⁡−1(x/a)\frac{1}{a}\tan^{-1}(x/a)
∫1a2−x2 dx\int \frac{1}{\sqrt{a^2 - x^2}}\,dxsin⁡−1(x/a)\sin^{-1}(x/a)

The key is identifying patterns that match derivative rules in reverse.